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Question 1

Question 2

Решите задачу:

$3 \frac{5}{6} +9 \frac{5}{24} =3 \frac{5*4}{6*4} +9 \frac{5}{24} =3 \frac{20}{24} +9 \frac{5}{24} =12 \frac{25}{24} =13 \frac{1}{24} \\ \\ \\ 1 \frac{5}{6} +7 \frac{13}{15} =1 \frac{5*5}{6*5} +7 \frac{13*2}{15*2} =1 \frac{25}{30} + 7\frac{26}{30} =8 \frac{51}{30} = \\ \\ \\ =9 \frac{21}{30} =9 \frac{21:3}{30:3} =9 \frac{7}{10} \\ \\ \\$

$\frac{11}{21} + \frac{1}{10} = \frac{11*10}{21*10} + \frac{1*21}{10*21} =\frac{110}{210} + \frac{21}{210} = \frac{131}{210} \\ \\ \\ 3 \frac{14}{19} + \frac{7}{19}= 3 \frac{14+7}{19}=3 \frac{21}{19} =4 \frac{2}{19} \\ \\ \\ 8\frac{1}{13} +5=13\frac{1}{13} \\ \\ \\$

$10 \frac{3}{14} + \frac{11}{14} =10 \frac{3+11}{14}=10 \frac{14}{14}=11 \\ \\ \\ 3 \frac{1}{11} +7 \frac{1}{11} =10 \frac{1+1}{11} =10 \frac{2}{11} \\ \\ \\ 10 \frac{11}{30} +1 \frac{1}{4} =10 \frac{11*2}{30*2} +1 \frac{1*15}{4*15} =10 \frac{22}{60} +1 \frac{15}{60} =11 \frac{37}{60}$

Отвечаем правильно

Помогите буду очень благодарен за помощь