Пожалуйста помогите.

Question 1

Question 2

$\left \{ {{y-xy-3x=3} \atop {2y+xy+x=-2}} \right. \ \textless \ =\ \textgreater \ \left \{ {{y-xy-3x=3} \atop {2y+xy+x+2=0}} \right. \ \textless \ =\ \textgreater \ \left \{ {{y-xy-3x=3} \atop {(2y+2)+(xy+x)=0}} \right. \ \textless \ =\ \textgreater \ \\ \\ \ \textless \ =\ \textgreater \ \left \{ {{y-xy-3x=3} \atop {2(y+1)+x(y+1)=0}} \right. \ \textless \ =\ \textgreater \ \left \{ {{y-xy-3x=3} \atop {(y+1)(2+x)=0}} \right.$

y + 1 = 0 2 + x = 0
y = -1 x = -2

подставляем найденные значения х и у в первое уравнение неравенства
-1 - x * (-1) - 3x = 3 y - (-2) * y - 3 * (-2) = 3
-1 + x - 3x = 3 y + 2y + 6 = 3
-2x = 4 3y = -3
x = -2 y = -1

Ответ: (-2: -1)

Senpoliya_zn · Answer 1 · 2018-04-26T03:21:56+0000

$\left \{ {{y-xy-3x=3} \atop {2y+xy+x=-2}} \right. \ \textless \ =\ \textgreater \ \left \{ {{y-xy-3x=3} \atop {2y+xy+x+2=0}} \right. \ \textless \ =\ \textgreater \ \left \{ {{y-xy-3x=3} \atop {(2y+2)+(xy+x)=0}} \right. \ \textless \ =\ \textgreater \ \\ \\ \ \textless \ =\ \textgreater \ \left \{ {{y-xy-3x=3} \atop {2(y+1)+x(y+1)=0}} \right. \ \textless \ =\ \textgreater \ \left \{ {{y-xy-3x=3} \atop {(y+1)(2+x)=0}} \right.$

y + 1 = 0 2 + x = 0
y = -1 x = -2

подставляем найденные значения х и у в первое уравнение неравенства
-1 - x * (-1) - 3x = 3 y - (-2) * y - 3 * (-2) = 3
-1 + x - 3x = 3 y + 2y + 6 = 3
-2x = 4 3y = -3
x = -2 y = -1

Ответ: (-2: -1)

Отвечаем правильно

Пожалуйста помогите.